Question

Question 3 (1 point) Calculate the specific heat for the element Madeupium if the addition of 118.3J increases the temperature of a 13.8 g sample by 17.2 K A) 94.9 J/g°C B) 148 J/g°C OC) 0.498 J/g°C D) 2.01 J/g°C Question 4 (1 point) 0.839 g of an unknown organic liquid was burned in a bomb calorimeter, heating the 395 grams of water by 11.1°C. Assuming the calorimeter absorbs a negligible amount of heat, calculate the heat added to the water in kJ/g. Your Answer: Answer units

Answer 1

Question 3.

Correct option: C

Explanation:

Heat absorbed by Madeupium = 118.3 J

Temperature difference, $\Delta T$ = 17.2 K = 17.2 ^oC         ($\because$ difference of temp in K = difference of temp in ^oC)

Mass of Madeupium (m) = 13.8 g

Let us say that the specific heat capacity of Madeupium = s

Now, heat energy absorbed = m x s x $\Delta T$                 

or, 118.3 J = 13.8 g x s x 17.2 ^oC

or, s = 0.498 J/g.^oC