Oxidation number of Na = +1
Oxidation number of O = -2
lets the oxidation number of As be x
use:
1* oxidation number (Na) + 2* oxidation number (O) + 1* oxidation number (As) = net charge
1*(+1)+2*(-2)+1* x = 0
-3 + 1 * x = 0
x = 3
So oxidation number of As = +3
Answer: +3
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