Question

The block shown in (Figure 1) has mass m 7.0 kg and foxed smooth trictionless plane tited at an angle 0 26.5 horizontal les on a Express your enswer unree sgea ngures anu inoue e apprupriae unns to the a 4.37 Subt Previous Anawers Correct Part B the block starts from rest 11.4 mup the plane from its base, what will be the block's speed when it reaches the botom of the incline? Express your answer to three significant figures and include the appropriate units Figure 1 of 1 x-10 3 Value Units You have already submitted this answer. Enter a new answer No credit lost. Try again Submit Previeus Anawrs Reest Answer

Answer 1

Here,

part B) let the speed at the bottom is v

Now, as the acceleration is a = g * sin(theta)

a = 9.8 * sin(26.5) = 4.37 m/s^2

Using third equation of motion

v^2 - u^2 =2 * a * s

v^2 - 0^2 = 2 * 4.37 * 11.4

solving for v

v = 9.98 m/s

the block's speed at the bottom is 9.98 m/s