200 ml of buffer needed using stock solutions of .196M HCHOO and .271M NaCHOO. compute volume...
Homework Answers
Henderson - Hasselbalch equation is
pH = pKa + log([A-]/[HA])
4.4 = 3.75 + log( [ HCOO-]/[HCOOH])
log([HCOO-]/[HCOOH]) = 0.65
[HCOO-]/[HCOOH] = 4.467
moles of HCOO-/moles of HCOOH = 4.467
( 0.271mol/1000ml) × X / (0.196mol/ 1000ml) × ( 200ml - X) = 4.467
X 0.000271mol/ml / ( 0.0392mol - X 0.000196mol/ml) = 4.467
X0.000271mol/ml = 0.1751mol - X0.0008756mol/ml
X0.001147mol/ml = 0.1751mol
X = 152.7ml
200ml - 152.66ml = 200ml - 152.66ml = 47.3ml
Therefore,
Volume of 0.196M HCOOH required = 47.3ml
Volume of 0.271M NaHCOO required = 152.7ml
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200
ml of buffer needed using stock solutions of .196M HCHOO and .271M
NaCHOO. compute volume...
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