a) You need to make an aqueous solution of 0.194 M sodium phosphate for an experiment in lab, using a 250 mL volumetric flask. How much solid sodium phosphate should you add?
b)How many milliliters of an aqueous solution of 0.229 M ammonium iodide is needed to obtain 6.59 grams of the salt?
a)
volume , V = 250 mL
= 0.250 L
use:
number of mol,
n = Molarity * Volume
= 0.194*0.25
= 4.85*10^-2 mol
Molar mass of Na3PO4,
MM = 3*MM(Na) + 1*MM(P) + 4*MM(O)
= 3*22.99 + 1*30.97 + 4*16.0
= 163.94 g/mol
use:
mass of Na3PO4,
m = number of mol * molar mass
= 4.85*10^-2 mol * 1.639*10^2 g/mol
= 7.951 g
Answer: 7.95 g
b)
Molar mass of NH4I,
MM = 1*MM(N) + 4*MM(H) + 1*MM(I)
= 1*14.01 + 4*1.008 + 1*126.9
= 144.942 g/mol
mass(NH4I)= 6.59 g
use:
number of mol of NH4I,
n = mass of NH4I/molar mass of NH4I
=(6.59 g)/(1.449*10^2 g/mol)
= 4.547*10^-2 mol
use:
M = number of mol / volume in L
0.229 = 4.547*10^-2/ volume in L
volume = 0.199 L
volume = 199 mL
Answer: 199 mL
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