Question

Consider the initial-rate data at a certain temperature in the table for the reaction described by Initial rate (M/s [NO210 (M) [031o (M) 2 NO2 (g)O(g) N20g(g)02(g) 3.12 x 104 0.650 0.800 5.28 x 104 1.10 0.800 14.78 x 104 176 1.40 Determine the value and units of the rate constant, k Units:

Answer 1

Please like this answer. THANK YOU

Given + Reaction Dorbzlby 2N0219) + 02191 → N20319) +20, (g) rate= * [Nou]a[03] i where *= Hate constant Tabley ( 1 1 [NO].M 0.650 1.10 1.76 I [0₂] M 0.800 0.800 I 1.40 Initial rate (MS) 3.12 x 104 5.28 X 104 14.78X104 lini - from i andrii b K[0-650] (0.500) = 3-12X104 [1-10]" [O-SUD] b = 5.28X104 fe dividing cu androi, we get 10.65019 ( 1.10 ) 3.12 5.29 upom solving we get 1a=1 fromcii andavi K [1.10)' (0.800] K[1-76] [1.403b = 5.28 X104 = 14.788104 divide (il, & 0.8005- 5.28 X1:76 11.40 14.78 1.10 upon solving b=II Hence order of the reaction = 2 rate KENO2] [₃] from 3.12 X 104 MIS = K (0.650) M (0.800) M K= 68104 irak constant : 68104 MS unita Malst

Please comment if you have any doubts about this answer.

All the best for your future.