Question

can someone please explain how to do this? I am very confused and it is due tomorrow.

Directions: Write the null and alternate hypothesis, determine the appropriate t-test for cach of the following problems, decide upon a decision rule, draw the rejection region, and write a statement that describes the relationship the researcher is entitled to make. (You may use Excel to calculate means, variance and standard deviation). 11 An investigator believes that families in Virginia have more children on average than the average number of children in the population of the United States. From census data the investigator knows that the mean number of children in the U.S. is 2.1 children. She draws a sample of seven families from the state of Virginia and obtains the number of children for each family. The data from this sample are presented below. Write the null and alternative hypotheses for testing the investigator's prediction. Scores for the seven families: 3, 6, 2, 0, 4, 6, 7

Answer 1

from the given dato, we have ** EX=284 sa Vimi ll *-7)39 - V (3- 4 + (7-459) =V633 : 2.5166 Hypothesis Ho: l = 2.1 Hail) 2.1 This is a right tailed dest rest statistics A 2-Ų Shun 4-2.1 - 2.5166/87 1.9975 ~11.998) Al cigion Rule degree of freedom (dl) = n1 = 77=6 since the confidence level is not given assumed confidence Dever a 95%. Q: 1-0.99: 0.05 A critical - tous, 6 = 11.943) Rejection . i region 1.943

Rejects the null hypothesis, if Issat 1.943 Decision reject the null hypothesis, since Istars Acritical , go Conclusion There is sufficient evidence to support the claim that the mean no. Children is greater than 2.1.