Question

I need three separate solutions for each wavelength i observed: 6566, 4662, 4090 Angstrom

• Calculate high for each transition - Using the Rydberg equation (Equation 2) where n, - 2 and n2 hich, calculate high for each spectral line (transition, wavelength) observed. Pay attention to units. Compare your calculated high value against the high value of the initially assigned transitions,

Answer 1

1 Give that Rydberg equation is 1/$\lambda$ = R_H (1/n1^{2 -} 1/n₂²₎

--For wavelength of 6566 Angstrom, (1/6566*10^-8) = 109737.3(1//4-1/n₂²₎

Therefore, higher energy level, n2 = 3

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For wavelength of 4662 Angstrom, (1/4662*10^-8) = 109737.3(1//4-1/n₂²₎

Therefore, higher energy level, n2 = 4

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For wavelength of 4090 Angstrom, (1/4090*10^-8) = 109737.3(1//4-1/n₂²₎

Therefore, higher energy level, n2 = 6