Given the concentration of sulfide is 0.5 mM. i.e. 1 liter of sulfide contains 0.5 milli moles (which is 500 micromoles).
Thus 0.2 ml of the sulfide sample will contain = 0.2 * 500/1000 = 0.1 micromoles
Similar calculation is done for other amounts of sulfide
Tube | 0.5mM sulfide standard (ml) | Sulfide amount (micromoles) | Sulfide (reagent (ml) | FeCl3 (ml) | H2O (ml) | Total volume (ml) | absorbance |
1 | 0 | 0 | 4.9 | 0.1 | 5 | 10 | 0 |
2 | 0.2 | 0.1 | 4.9 | 0.1 | 4.8 | 10 | 0.372 |
3 | 0.4 | 0.2 | 4.9 | 0.1 | 4.6 | 10 | 0.502 |
4 | 0.6 | 0.3 | 4.9 | 0.1 | 4.4 | 10 | 0.65 |
5 | 0.8 | 0.4 | 4.9 | 0.1 | 4.2 | 10 | 0.734 |
Plotting Absorbance as a function of sulfide amount (miromoles), we get,
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