Question
Hi I am im a biochemistry lab and we are doing an experiment titled: PCR Amplification of LeuRS F C Terminal Domain. I am having troubles figuring out the rest of my caluclations.



If the average of your weights pipettes, or more than 5% off for the pipet, what is the average value of your masse your weig
Dilutions -set I miv=mara (a) s (9.1757 = 1,8353, 912V1 = (1-3) Lleni )-0.2m 200mA loocm/-200ml=800mitteo XOOO w 2019,18%) =

I already did the calculations for the first dilution set, I was wondering how I would do the calculation for the second dilution set.


Assuming the 0.1% extinction coefficient for BSA is 0.667 (mgmL.)cm, calculat absorbance values of your diluted solutions at

Also I was wondering how I would determine the theoretical values for my data. Is there a specific formula I can use?
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Answer #1

They are asking to do the dilutions in serial way. That is: you have to do the "smallest" dilution (1/5) from the standard solution, the following (1/20) from the 1/5 and the following (1/100) from the 1/20. Serial dilutions would be something like "diluting the previous dilution".

So now, the calculations:

  • The 1/5 dilution from the standard solution is exactly the same as in the first dilution set: 200 mL of BSA and 800 mL of water. Now, using the dilution formula, we can calculate the concentration in this solution:

Vi*C C2 = - 200mL * 9mg/mL = 1.8mg/ml 1000mL V

  • Now, for the 1/20 dilution, we can calculate the concentration it should have, which is 1/20 of the original concentration. That is: 9/20 = 0.45 mg/mL. Now we have to calculate the volume of dilution 1/5 we need to take to prepare this. Dilution 1/5 has a concentration of 1.8 mg/mL and we need a final volume of 1 mL. We use the same dilution formula to calculate V1 (the volume of 1/5 dilution):

Vi=- V2 * C2 C 1000mL *0.45mg/mL = 250mL 1.8mg/mL

We have to take 250 mL of the 1/5 dilution to prepare the 1/20 dilution.

  • Now it's the same thing, but we have to prepare de 1/100 dilution (which is equivalent to a concentration 0f 0.09 mg/mL) from the 1/20 dilution (which has a concentration of 0.45 mg/mL):

V2 * C2 Vi=- 1000mL * 0.09mg/mL = 200mL 0.45mg/ml C1

We need 200 mL from the 1/20 dilution to obtain de 1/100 dilution.

To calculate the theoretical data of absorbance there is in fact a formula:

Abs=s* *

Where epsilon is the given value of 0.667 (mg/mL)-1 cm-1, l is the optical path, which is usually 1 cm for spectrophotometers and c is the concentration. Thus, by multiplying the calculated concentrations by 0.667, yo will get the theoretical absorbance values.

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