Question

2. (a) Draw the products for the following Snl reactions. (0.5 pt ea) (b) Designate all asymmetric carbons as R or Sor racemic. (0.5 pt ea) cH:OH + I Br Br H:O: + 40: 1 28 -

Answer 1

Since, all the given reactions are the SN1 reaction in which stable carbocation forms as an intermediate. This is the reason only racemic mixture forms in all the reaction. In the first step formation of the carbocation takes place and finally product will form. If any carbon atom has all the different group attached then only it is called as asymmetric carbon. The complete reaction with the step wise mechanism is given as below:-

0. I - (sinal product that du et) H No Ross because no stereo center,

De ene t cheon → Doct cheon S) Racemic mixture +HBr (By pro duct).

Cắt mỏi , e thổ -> ses too → Köm non (major product) No'r ors configuration because here is no any chiral centers.