Answer:-
This question is solved by using simple formula of calorimetry which states that heat lost is equal to the heat gained.
The answer is given in the image,
Q=mcAT Creiger Quantity Heat = Mass x Specific Heat x (Temp final - Temp initial) A...
Energy/Specific Heat (q=mcAT) 1. Determine the energy, in Joules, needed to increase the temperature of 20.00 g of water from 300.0 K to 365.0 K. (Remember that one degree of Celsius contains the same amount of energy as one Kelvin.) 2. Determine the energy, in Joules, released as 1.00 kilogram of water cools from 72.0°C to 30.0°C. 3. 25.0 g of mercury are heated from 25.0° C to 155.0°C and absorbs 455 joules of heat in the process. Calculate the...
WATER Table Mas Initial Final Temp Temp Temp. Chang Mas METAL Initial Final emp. Temp Chang Respond to the questions/problems below. Questions/Problems 1. Equal masses of water a Styrofoam cup. The water has a speci has a specific heat of 0.113 cal/g °C lasses of water at 20°C and iron at 40°C are put together in a cup. The water has a specific heat of 1 cal/g °C and the iron specific heat of 0.113 callao What do you think...
4. Heat transfer: q = mass x Cs x ΔT and –qreaction = +qsolution a. A piece of metal with a mass of 8.6 g was heated to 100.0°C and dropped into a coffee cup calorimeter containing 402.4 g of water at 25.0°C. If the temperature of the water and the metal at thermal equilibrium is 26.4°C, what is the specific heat of this metal in J/g°C? b. How much heat energy must be added in order to boil a...
Lab-10: Calorimetry: Specific Heat of a Metal DATA SHEETS: Reference: Chapter Notes-10 and Lab Manual (Pages 64 to 70) Use the following You Tubes to get more information https://youtu.be/8gHFOL2990U https://youtu.be/HlvilF6MI9c Calculate the Specific Heat and identify the Metal Observation Mass Mass of Metal (ml): 87.87 g Mass of polystyrene cup (m2): 2.32 g Mass of cup with water (m3): 72.82 g Mass of water in the cup (m3-m2): 70.5 g Temperature Initial temp. of Metal (the boiling water temperature (t1):...
The specific heat c is the amount of heat necessary to change the temperature of 1.00 kg of mass by 1.00°C. The specific heat c is a property of the substance; its Sl unit is J/(kg · K) or J/(kg.°C). Recall that the temperature change (AT) is the same in units of kelvin and degrees Celsius. water silver copper cup Case 1: A 0.780-kg silver pellet with a temperature of 85 °C is added to 0.150 kg of water in...
what is the specific heat of this metal? Water 'Cd Initial I. Einal I. Mass 22.0°C 25.0°C 100.0g 100.0°C 25.0°C 58.953g q=mcat
Calculate final temp of water when a 3.00 g piece of iron at 85.0°C (Specific heat 0.45 J/g °C; density = 7.05 gmL ) is added to 35.0 mL of water (initial temp is 22.5°C) Density of water. 1.00g/mL; Specific heat of water: 4.18 J/g oC
FIRST RUN: (a) Mass of the Calorimeter (two empty cups) in g: 4.0g (b) Mass of the cold water and the calorimeter in g: 52.5g (c) Calculated mass of the coldwater in g [(b)-(a)]: 48.5 (d) Temp. of the Cold Water in C: 14c (e) Temp. of the Hot Water before mixing with the cold in C: 38c (f) Mass of the Cold & hot water mixed AND the calorimeter in g: 100.6g (g) Calculated Mass of the Hot water...
1) For part A, calculate q (the heat lost in calories) for copper and lead. The specific heats of these metals are in the background section. Then calculate q (the heat gained in calories) for the water in each case. Remember that you used 25.0 g of water in the experiment. Show your calculations 2)The heat lost by the metal and the heat gained by the water should be the same. Are they? If not, list possible sources of error....
please answer all questions Temperature Change and Phase Change - Specific Heat and Latent Heat - From COLD ICE to Warm Water The quantitative relationship between heat transfer and temperature change is Q = mcAT, where Q is heat transfer, m is the mass of the substance, and AT is the change in temperature. The symbol c stands for specific heat which depends on the material and phase (for exmample, water and ice have different specific heat). The specific heat...