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WATER Table Mas Initial Final Temp Temp Temp. Chang Mas METAL Initial Final emp. Temp Chang Respond to the questions/problems
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Answer #1

Answer

Solve by Energy/Heat conservation law.

Heat gain or loss by water = Heat Loss or gain by iron

we know that

Q=m.s.AT   

where m is mass of body, s is specific heat

and \Delta T is temperature difference.

let final temperature is Tf

Qwater = Qiron

m.s ( Tf - T1) = m.s.(T2 - Tf )

1 x  (Tf - 20) = 0.113 x (40- Tf )

on solving

Tf = 22.03 0C .

Answer 2

this questions also done by same method. but one thing is extra i.e. latent heat of ice. latent heat of ice also adds.

but some data missing for questions one is image and another is latent heat of ice.

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