Here we are given that class width must be 2000. That means difference in lower ( or upper ) limits of two classes is 2000.
Hence we have that frequency distribution table as :
0 | 1999 | 17 |
2000 | 3999 | 10 |
4000 | 5999 | 2 |
6000 | 7999 | 0 |
8000 | 9999 | 1 |
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Question 4 of 4 (1 point) View.problem in a pop-up 2.2 Section Exercise 33ab addresses. Check Answ 8445 3801 1125 2073 "2242 2308 4467 1125 3838 4776 1883 1340 1807 1128 3967 3318 1681 5433 2446 8445 8445 3801 2170 2158 3318 2158 2158 5433 1340 135 Solve It Guided Solu Show Exam Ask My Instr Link to Texth Tables Formulas Source: www.infoplease.com Download data Part 1 out of 3 Construct a frequency distribution using a class width of 1500,...
Question 4 of 4 (1 point) Vi 2.2 Section Exercise 33ab 8445 3801 1125 2073 2242 2308 4467 1125 3838 4776 1883 1340 1807 1128 3967 3318 1681 5433 2446 8445 8445 3801 2170 2158 3318 2158 2158 5433 1340 135 Download data Link to Textbook Tables Part 1 out of 3 limit for the first class. Number of Words