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7 Find the 90% confidence interval for the population standard deviation given the following (1 point n 55, -11.49,s 2.34 and the distribution is normal. 0192 <σ<3.25 o 2.09 2.92 1.37<σ< 1.01 10.28 σ< 14.32 8. Twelve different video games showing product placement were observed and the duration ( point) times of game play (in seconds) were recorded and found to have a normal distribution. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Given a sample standard deviation of 60.9 sec, use the sample data to construct a 99% confidence interval estimate of σ, the standard deviation of the duration times of game play 050 sec < ơ < 16.0 sec 38.0 sec < ơ< 115.2 sec 42.6 sec < σ< 121.7 sec 39.0 sec < 125.2 sec
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7)

here n = 5.48 Critical value for 54 degree of freedom and 90 % CI are as follows 38.116 X 0.95 72.153 (n-1)s /x 4.098 7.757 2.024 2.785

from above nearest correct option 90% CI : 2.09 < sigma < 2.92

8)

here n = 12 3708.81 Critical value for 11 degree of freedom and 99 % CI are as follows 2.603 0.005 0.995 26.757 (n-1)yr (n-1)s /x 2.6590 1524.719 15673.035 1.5514 2.2706 39.048 125.192

from above 99% CI =39.0 sec < sigma < 125.2

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