Question

Question 3

An automated egg carton loader has a 3% probability of cracking an egg, and a customer will complain if 1 or more eggs are cracked. Assume each egg load is an independent event. What is the probability that a box of a 12 eggs results in a complaint?

	a.	o.25
	b.	0.31
	c.	0.47
	d.	0.73

Answer 1

Answer

We know that the probability is given as p= 3% = 3/100 = 0.03

Sample size is given as n = 12

There will be a complaint only if 1 or more eggs are cracked.

So, we can say that

Probability of one or more eggs cracked = 1- Probability of zero egg cracked. .............................equation 1

Using the binomial formula

where r = 0, n = 12 and p = 0.03

setting the values, we get

this gives us

setting this value in equation 1, we get

Probability of one or more eggs cracked = 1- Probability of zero egg cracked = 1 - 0.6938 = 0.3062 or 0.31

So, option B is correct answer