Total number of balls : 2+3 = 5
Let R shows the event that red ball is selected and B shows the event that blue ball is selected. So we have
P(R) = 2/ 5 = 0.40, P(B) = 3/5 = 0.60
(a)
When a red ball is selected then fair coin is tossed so X has binomial distribution with parameters n=3 and p=0.50. So,
(b)
When a blue ball is selected then fair coin is tossed so X has binomial distribution with parameters n=3 and p=0.60. So,
(c)
By the law of total probability
(d)
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