Question

A student reacted 4.7 mL of ethanol with 15 mL of acetic acid. The density of...

A student reacted 4.7 mL of ethanol with 15 mL of acetic acid. The density of ethanol is 0.789 g/mL and the density of acetic acid is 1.049 g/mL.   She recovered 3.58 grams of pure ester. Calculate the experimental % yield.  Give answer as XX. (No % sign) EsterTheoYield.jpg

0 0
Add a comment Improve this question Transcribed image text
Answer #1

1760.052 g mol-1 I can of H-0 CHetta eltze-o-cheltz J I ethyl acetate CEA Moles of ethanol = (407rul * Or 789 g/ml) 746007gmo

Add a comment
Know the answer?
Add Answer to:
A student reacted 4.7 mL of ethanol with 15 mL of acetic acid. The density of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • acetic acid is 25 ml and alcohol is 20 ml The synthesis of an ester by...

    acetic acid is 25 ml and alcohol is 20 ml The synthesis of an ester by the reaction of a carboxylic with an alcohol is an equilibrium reaction. H - R-OH HO ROH R OR, Recall from general chemistry that, according to Le Caiclista principle, an equilibrium can be shifted toward greater product formation by using an excess of reactant or by removal of a reaction product as it forms. 1. Are any products removed during the reaction period (the...

  • A student needs 15.0 grams of ethanol for an experiment. If the density of ethanol is...

    A student needs 15.0 grams of ethanol for an experiment. If the density of ethanol is 0.789 g/mL, how many milliliters of ethanol are needed? (use numbers only and do not include units)

  • Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with...

    Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass.

  • A) A student weighed out 3.52 g. of salicylic acid in a 100 mL flask and...

    A) A student weighed out 3.52 g. of salicylic acid in a 100 mL flask and adds 2.3 mL of acetic anhydride (density= 1.080 g/mL). Determine the maximum(theoretical) number of grams of acetylsalicylic acid she can prepare. B) If the student obtained 4.21 g. of aspirin, calculate the % yield. Briefly, explain why she might have obtained this amount of product.

  • A liquid-phase mixture of 450 mL of acetic acid, 300 mL of ethanol, 2.00 mL of...

    A liquid-phase mixture of 450 mL of acetic acid, 300 mL of ethanol, 2.00 mL of water, and 2.00 mL ethyl acetate are mixed together at 298 K, where the following reaction will occur: CH3COOCH2CH3 +H2O  CH3COOH +CH3CH2OH, Kc = 3440 Will the reaction occur from left-to-right or right-to-left (as written)? Please support your answer. (Hints: Can you calculate concentrations of the chemical species initially in appropriate units. Starting with the densities, i.e., specific gravities, and volumes, molar amounts...

  • Need help with freezing point depression expeiment volume of acetic acid 30 volume of unknown solute...

    Need help with freezing point depression expeiment volume of acetic acid 30 volume of unknown solute in solution1    1.5 volume of unknown solute in solution 2 1.5 freezing point of pure acetic acid 16.3 freezing point of solution 1 14.5 freezing point of solution 2 11.3 average molar mass of unknown solute Calculations for Part 1 The density of acetic acid is 1.049 g/mL and Kf(acetic acid) =3.90 °C·kg/mol The density of the unknown is 0.791 g/mL. 1.Calculate the masses...

  • 2. Based on the starting amounts of salicylic acid (2.00 g) and acetic anhydride (2.70 mL), which reactant is the l...

    2. Based on the starting amounts of salicylic acid (2.00 g) and acetic anhydride (2.70 mL), which reactant is the limiting reagent? The density of acetic anhydride is 1.08 g/mL. Show your calculations. YAVOITVIETOAT 3. Based on Question 2, if a student recovers 1.83 grams of pure, dry aspirin, what is her percent yield? Show your calculations.

  • just need answer, which letter. TAL 1. (20pts) A student reacted 4.0 g of 2-hydroxybenzoic acid...

    just need answer, which letter. TAL 1. (20pts) A student reacted 4.0 g of 2-hydroxybenzoic acid (C H6O3, MW 138 g/mol) with 4.0 mL of acetic anhydride (CH603, MW 102 g/mol) and 1 g of concentrated sulfuric acid.(MW 98) After workup, the student isolated 2.5 g of aspirin (MW 180). The density of acetic anhydride is 1.08 g/mL. (atomic weights: C. 12, H 1; 0, 16, S. 32) 1a. The limiting reagent is a) 2-hydroxybenzoic acid b) acetic anhydride c)...

  • 4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted...

    4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...

  • Aspirin can be sunthesized in the lab by combining salicylic acid (C7H6O3) and acetic anhydride (C4H6O3)...

    Aspirin can be sunthesized in the lab by combining salicylic acid (C7H6O3) and acetic anhydride (C4H6O3) to form aspirin (C9H8O4) and acetic acid (C2H4O2). The balanced equation for this reaction is C7H6O3+C4H6O3⟶C9H8O4+C2H4O2 A student started with 4.45 mL acetic anhydride (density=1.08 g/mL) and 2.34 g salicylic acid. The student synthesized 2.47 g of aspirin. Calculate the theoretical yield of aspirin (C9H8O4) in grams Calculate the percent yield for aspirin (C9H8O4)

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT