Question

14 & 15. can you show step by step please?

14. The client is to receive a 2 mg/min infusion of lidocaine hydrochloride. The drop factor is 60 gtt/mL. The order calls for the addition of 500 mg of lidocaine hydrochloride to 250 mL of D5W. a. An IV pump would be programmed for b. If the infusion is administered by gravity, the IV flow rate would be set for per minute. mL/hr. drops Round final answers to the nearest whole number, as applicable. 15. The order calls for the administration of 0.35 mcg IV per minute of alprostadil. Add 575 mcg of alprostadil to 250 mL of D5W. The drop factor is 60 gtt/mL. drops per minute. Round final answer to the nearest whole The flow rate will be set for number, as applicable.

Answer 1

14. Ordered dose 2 mg/min of lidocaine hydrochloride.

250ml of D5W contains 500mg of lidocaine hydrochloride.

Then

500mg + 250ml = 2mg/ml

It means 1 ml of D5W contains 2 mg of lidocaine hydrochloride.

Order dose was 2mg per minute then, /hr

60minute x 2mg = 120mg

It means the patient needs 120 mg per hour. 1 ml contain 2 mg and 60 ml contain 120 mg of lidocaine hydrochloride.

Answer a. Iv pump would be programme for 60ml/hr

Answer b. The formula for drop calculation is

Total Volume = time x drop factor

60ml = 60min x 60gtt/ml = 60drops/min

So, iv flow rate will set for 60 drops per minute.

No 15.

Order dose 0.35 mcg/min means,

0.35mcg x 60minute = 21mcg/hr

250 ml D5W contains 575mcg of alprostadil.

Drop factor 60 gtt/ml

So, 0.43 ml of D5W contains 1 mcg of alprostadil.

250ml = 575mcg=0.43ml

So, 21mcg is in 9ml

21mcg x 0.43ml = 9.03ml

According to the formula of drop calculation

9ml - 60min x 60gtt/ml = 9drops/min

Answer is the flow rate will be set for 9 drops/min