The present worth of all costs is calculated as follows
For the first 5 years, the present worth of costs is found using the present value of annuity equation. After the 5th year, the operating costs increases by 10% and the interest rate is also 10% i.e. ( r = g) . The present value of growing annuity when r = g is nA , where n is the number of years and A is the annuity amount.
Present worth of all costs for a newly acquired machine is determined to be = $ 185,721.97 $ 185,722
Present worth of all costs for a newly acquired machine is determined to be = $ 185,722
Calculate the present worth of all costs for a newly acquired machine with an initial cost...
Calculate the present worth of all costs for a newly acquired machine with an initial cost of $34,000, no trade-in value, a life of 14 years, and an annual operating cost of $17,000 for the first 3 years, increasing by 10% per year thereafter. Use an interest rate of 10% per year. The present worth of all costs for a newly acquired machine is determined to be $
What is the present worth of a machine with an initial cost of $41,000, an annual cost of $6,000 per year, a salvage value of + $12,000, a useful life of 7 years, and a financing cost rate of 5% per year?
The annual maintenance costs associated with a machine are $1000 for the first 10 years and $2000 thereafter. The machine has a 30 year life. What is the present worth of the annual disbursements if the interest rate is 12%?
With the estimates shown below, Sarah needs to determine the trade-in (replacement) value of machine X that will render its AW equal to that of machine Y at an interest rate of 9% per year. Determine the replacement value. Machine X Machine Y Market Value, $ ? 92,000 Annual Cost, $ per Year −55,500 −40,000 for year 1,increasing by 2000 per year thereafter. Salvage Value 15,500 17,000 Life, Years 3 5 The replacement value is $ ________.
What is the annual worth of a machine with a first cost of $180,000, an annual operating cost of $14,500 per year, no overhaul cost, a salvage value of $16,000, a useful life of 10 years, and a cost rate of 4% per year?
Compare alternatives A and B with the present worth method if the MARR is 11% per year. Which one would you recommend? Assume repeatability and a study period of 12 years. $25,000 $10,000 at end of year 1 and increasing by $1,000 per year thereafter None Capital Investment Operating Costs $55,000 $5,000 at end of year 1 and increasing by $500 per year thereafter $5,000 every 3 years 12 years $10,000 if just overhauled Overhaul Costs Life 6 years negligible...
5. The data for new and used machines are shown below: Initial cost($) Annual operating cost ($/year) Salvage value (5) Life (years) Used machine 15,000 8,000 5,000 New machine 40,000 2,000 10,000 Use an interest rate of 7% per year. a) Find the present worth of the new machine b) Compare the PW of the used machine to the new c) If each machine were to be funded using an annual payment load at 8%, how much would the annual...
Problem 1 The City of Miami plans to purchase an important machine. The initial cost is determined to be 250,000. It is estimated that this new equipment will save $110,000 the first year and increase radually by $35,000 for the next 6 years. MARR:10%, what is the Net Future worth of this investment? $1, Problem 2 For the cash flows given in the table below, evaluate the unknown value "A". Use an interest rate of 6%. 0 $25,000 Year Cash...
Compare alternatives A and B with the present worth method if the MARR is 10% per year. Which one would you recommend? Assume repeatability and a study period of 20 years $15,000 $45,000 Capital Investment Operating Costs $4,000 at end of year 1 and increasing by $400 per year thereafter $4,000 every 5 years 20 years $8,000 at end of year 1 and increasing by $800 per year thereafter None Overhaul Costs Life 10 years Salvage Value $8,000 if just...
please dont use excel, show me the formula used 5. Machines that have the following costs are under consideration for a robotized welding process. Using an interest rate of 10% per year, determine which alternative should be selected on the basis of a present worth analysis. Machine X Machine Y First cost, $ Annual operating cost, $ per year Salvage value, $ Life, years - 250,000 --60.000 70.000 -430.000 -40,000 95.000