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Problem 1 The City of Miami plans to purchase an important machine. The initial cost is...
In comparing alternatives, I and J by the present worth method, the equation that yields the present worth of alternative Jis Alternativel Alternative Initial cost, -150,000 - 250.000 Annual Income, $ per year 20,000 40,000 Annual expenses, $ per year --9,000 -14,000 Salvage value, $ 25,000 35,000 Life, years The interest rate is 15% per year. (PWJ--250,000 + 40,000(PIA ,15%.6) + 35,000(P/F.15%,6 (PWJ --250,000 + 26,000(PIA ,15%,6) +35,000(P/F.15%,6 (PWJ - -250,000 - 26,000(PLA 15%,6) +35,000(P/F ,15%,6 (PW J--250,000 - 26,000(PIA...
Ch. Benefit / Cost Analysis Problem 1: ICON Co. will perform a project that will have a first cost of $1 million with an annual maintenance cost of $50,000 and a 10 year life. This project is expected to benefit the company with $250,000 per year. But also the lost income to the company is estimated to be $30,000 per year. At an interest rate of 6% per year, should the project be undertaken? Problem2:ICON Co. is planning to make...
for an alternative with an initial cost of $350 and an annual benefit of $47.50 that increases by $10 each years. use a 8-year useful life and an 6%MARR to calculate: A. Future worth? B. Standard Benefit-cost Ratio? C. Simple Payback Period?
Please help in this question all parts Chapter 8 Incremental Analysis (50 Points Problem 3 An oilcompany plans to purchase a large piee of vacant land for $77,500. There are four possible improvements over and above the cost of the land: Cost of s 75,000 Cost of $ 230,000 Cost of S 35,000 Cost of $ 135,000 Conventional service station Automatic car wash with pumps Discount self-service only Service station with quick car wash A. B. C. D. In cach...
Solve for A and B, Engineering Economy please solve it right! Question Help %) Problem 6-52 (algorithmic) Compare alternatives A and B with the present worth method if the MARR is 15% per year. Which one would you recommend? Assume repeatability and a study period of 20 years. $40,000 $7,000 at end of year 1 and increasing by $700 per year thereafter $7,000 every 5 years $15,000 $14,000 at end of year 1 and increasing by $1,400 per year thereafter...
Using incremental rate of return, determine which of the following options is the most cost effective provided a minimum annual rate of return (MARR) of 18%, a useful life of 10 years, and the following data: Option 1: Initial Cost: $50,000 Annual Cost: $7,000/ year with an annual increase of $500 each year Repair Cost at year 8: $20,000 Salvage Value: $35,000 Option 2: Initial Cost: $35,000 Annual Cost: $9,000/ year with an annual increase of $1,000 each year Repair...
Q3:1) For equal 20 years life at the interest rate of 6 %, which Design should be selected by using Benefit Cost Method (include DN alternative) (13 Marks) Design 1 Design 2 Construction cost, $ 15,000,000 10,000,0o0 Building maintenance cost, S/year Patient benefits, S/year 55,000 35,000 1,050.0ooo 800,0oo Conventional and solar the B/C ratio to determine which ii) alternatives are available for providing energy at a remote radar site. Use method should be selected at an interest rate of 12%...
Need cash flow diagram 04) Three mutually exclusive alternative are being considered Initial Cost Benefit at the end of the first Year Uniform Annual Benefits at end of subsequent years Useful Life in years $500 $200 $100 $400 $200 $125 $300 $200 $100 At the end of its useful life, an alternative is not replaced. If MARR is 10%, which alternatives should be selected? a) Based on the payback period? b) Based on benefit-cost ratio analysis c) Benefit/Costs Analysis using...
Question #1: Your company is considering the purchase of either machine A or machine B as shown in the following table: Initial cost Estimated life Salvage value Other costs Machine A $80,000 20 years $20,000 $18,000 per year Machine B $100,000 25 years $25,000 $15,000 per year for the first 15 years $20,000 per year for the next 10 years 1. If the interest rate is 10%, and all cash flows may be treated as end-of-year cash flows. Assume that...
Consider the data for the following two alternatives, Alpha & Omega. Use the benefit-to-cost ratio method to work out the problem. MARR = 8% Alternative Alpha Omega First cost $100,000 140,000 Operating costs/year 50,000 60,000 Benefits /year 100,000 120,000 Dis-benefits 30,000 25,000 Life in years 5 10 I Razón B/C = (EW of net benefits)/(EW of initial costs + EW of operating costs) EW - Equivalent Worth Determine the B/C ratio for Omega. Provide a result with two decimal places...