According to the question,
Initial administration dosage size = 250 mg
No. of doses per day = 3
Therefore, total dosage per day of Levodopa initially = 250 mg x 3 = 750 mg
Now, each dosage size is increased by 250 mg every 4th day. This occurs for 28 days.
Therefore, no. of times dose is increased = 28/4 = 7 times.
Now, increase in dosage size over 28 days = 250 mg x 7 = 1,750 mg
Initial dosage size = 250 mg
Therefore, maintenance dosage = Initial dosage + Increased dosage
= 250 mg + 1,1750 mg
= 2,000 mg
Therefore, each administration of maintenance dose is 2,000 mg or 2 gram. Since, 3 doses are administered each day, the total daily dosage in the maintenance period will be 3 x 2 gm = 6 grams.
Levodopa, a drug used in the treatment of parkinsons disease, has a small inital dose followed...
Levodopa, a drug used in the treatment of Parkinson’s disease, has a small initial dose followed by a steady increase over several days. Suppose a patient is given three doses a day. Each administration is 250 mg on the first day, and is increased by 250 mg every fourth day. The maintenance dose is reached after 28 days. Calculate the initial and final daily doses of levodopa administered to the patient.
Levodopa, a drug used in the treatment of Parkinson’s disease, has a small initial dose followed by a steady increase over several days. Suppose a patient is given three doses a day. Each administration is 250 mg on the first day, and is increased by 250 mg every fourth day. The maintenance dose is reached after 28 days. How large is each administration of the maintenance dose?
Pramipexole is another drug used in the treatment of Parkinson’s disease that, like levodopa, increases the effect of dopamine. An intial adult dose consists of 0.375 mg/day. This is increased by 0.375 mg/day every 5 days for 31 days. How large is the daily dose at the end of 31 days?
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