Activity | Most Optimistic | Most Likely | Most pessimistic | Expected completion time | Variance |
A | 2 | 5 | 11 | 5.5 | 2.25 |
B | 3 | 3 | 3 | 3 | 0 |
C | 1 | 3 | 5 | 3 | 0.444444 |
D | 6 | 8 | 10 | 8 | 0.444444 |
E | 4 | 7 | 10 | 7 | 1 |
Expected completion time = (Most optimistic+ Most pessimistic+4*Most Likely)/6
Variance = ((Most pessimistic - Most optimistic)/6)^2
Path | Duration |
A-B-D | 16.5 |
A-C-E | 15.5 |
Critical path = A-B-D with duration 16.5 weeks which is project duration and project variance = variance of critical path A-B-D = 2.694444444
Project standard deviation = sqrt(2.694444444) = 1.6414763
z-score for 0.82 probability is 0.92
So, 0.92 = (x-16.5)/1.6414763
or, x = 0.92*1.6414763 + 16.5 = 18.0101582 = 18 (Rounded to nearest whole number)
Problem 5-11 There is an 82 percent chance the project below can be completed in X...
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