Urgent, please solve only if you know how to use R. I've attached the data. Thank you!
Data:
traditional.training |
revised.training |
56 |
50 |
50 |
54 |
52 |
45 |
44 |
55 |
52 |
45 |
56 |
60 |
47 |
58 |
53 |
53 |
55 |
45 |
48 |
56 |
42 |
53 |
51 |
52 |
48 |
55 |
49 |
54 |
44 |
56 |
The two groups are independent of each other, So if X denotes the scores of employees who underwent traditional training and Y denotes the scores of employees who underwent revised training. To check if their means are equal or not, we do a two-sample t test.
After serving the data X and Y as input to R:
We need to type in the following commands, note that here , we assume that the under lying distribution is normally distributed and homoscedastic.
Since, p-value>0.05, we fail to reject the null hypothesis and conclude that there is no evidence to show that the two methods achieve different results.
Urgent, please solve only if you know how to use R. I've attached the data. Thank...
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