Question

17. One milliliter of plasma is diluted 1/10 in tube 1. Then 1 mL of the dilution in tube 1 is added to 4 mL in a second tube. One milliliter from tube 2 is then added to 9 mL diluent in tube 3. What is the substance (plasma) volume in the third tube? 18. What is the specific gravity of a substance if 5 mL of the substance weighs 6.5 g, but the substance is only 50% pure? 19.What is the g/mL of a commercial preparation of nitric acid if the label states: specific gravity 1.42 g/ml, purity 71%? 21. One milliliter of 100 pg/mL solution is diluted 1/10 in tube 1. Then 1 mL of the dilution in tube 1 is added to 9 ml in a second tube. One milliliter from tube 2 is then added to 9 mL diluent in tube 3. What is the substance concentration in the third tube? 23. A set of decreasing substance concentrations is made through a serial dilution in water. Each dilution is read on an instrument, and then a graph is drawn to find the relationship between instrument output and concentration. What is this graph called? 25. A serum sample is diluted 1/2, 1/4, 1/8, 1/16, and 1/32. Each serum dilution is tested for reaction to antigen. A reaction is observed in the 1/16 dilution but not in the 1/32 dilution. What is the antibody titer? 26. After 2 years of storage, an enzyme with a specific activity of 250 units/uL and a half-life of 6 months will have a specific activity of

Answer 1

17 17. ImL + " → 10mL To in Tubet 14 = 5m L Tube 2 ImL + 9mL =10mL in tube 3 ImL to Tube 1 ImL plasma 10 m L Iml ta oil ml plasma 10 - Tube 2 > 5mL → Iml 0.1 mL plasma 0.1 0.02 mL plasma Tube 3 = 0.02mL plasma Tubble 37 10ml Imle 0.02mL 0.02 0.002 nr Son L 19. 100 70.42 50% = 3.25 = 3.259 = 0.65 g/mol 6.5 6.5g is actually 50% of 6.5 = 3.25g. Purity 71% = 7 - 7 = 1.008 g/mL 100g = te = 70-42 mL (volume) 100 ug/mL to 10 ug/mL in Tuble I y Tubde 2 to 1 10 times dilution = leglma ImL with 9ml = Tube 3= 0.1 ug/mL Tube 3 to 2 21. lo ساm/هر 1-0

23. This is called calibration on stand standard curve. 25. antibody ti tena - greatest dilution len velit with activity 26. 2 years = 6 months X4 = 4 half-life 4 x 250 units / L = 250, 15-625 units JuL ofter 2 yore.