Question

the plan and section of a concrete footing are given below

H ola concrete footing are given below 36 PLAN OF FOUNDATION 25x2.5=1.5 ( 1,5=151-31 .375 SECTIONAL Calculate the volume of concrete in cubic yard required

Answer 1

Centre to centre length of Long walls = Lccl

Lccl = 25' 6'' - (1/2) 2' 6'' - (1/2) 2' 6'' = 23' 0''

Centre to centre of Short walls = Lccs

Lccs = 12' 7'' - (1/2) 2' 6'' - (1/2) 2' 6""= 10' 1''

Total number of Long walls = 2

Total number of Short walls = 2

Total Centre to centre length=Lcct

Lcct = 2 x 23' 0" + 2 x 10' 1" = 66' 2'' = 66.1667'

Volume of Concrete = Vc

Vc = (Centre to centre length) x (Width of an item) x (Depth of an item)

Vc = (66.1667' x 2.5' x 1.5')+(66.1667' x 1.5' x 3')

Vc = 248.125 ft3 + 297.75 ft3

Vc = 545.875 ft3

But we know that, 1 yard = 3 feet

Vc = 545.875 x (1/3)3 = 545.875 x 1/27

Vc = 20.21759259 cubic yard

Vc = 20.2176 cubic yard

Note: It is to be noted that the calculations done above are for 25' 6" x 12' 7" single rectangular room, which becomes simpler for calculations.

Calculations for Figure 1 and Figure 2 will be same.

k 256 1271 Figure - 1 A 1810²- - 23 127 Figure 2 A 256