p = 0.275 p^2 = 0.275 × 0.275 = 0.07562 q = 0.725 q^2 = 0.725...
p = 0.275 p^2 = 0.275 × 0.275 = 0.07562 q = 0.725 q^2 = 0.725 × 0.725 = 0.5256 2pq = 2 × 0.275 × 0.725 = 0.3987 p^2 + 2pq + q^2 = 0.99992 = approx. 1
What are the phenotypic ratio’s based on this Hardy Weinberg equilibrium? Please help me out thank you
Homework Answers
Answer:
Dominant phenotype = p^2 + 2pq = 0.07562 + 0.3987 = 0.47432
Recessive phenotype = q^2 = 0.5256
Phenotypic rati = 1:1
Use the Hardy-Weinberg equations (p2 + 2pq + q2 = 1 and p + q =...
Use the Hardy-Weinberg equations (p2 + 2pq + q2 = 1 and p + q = 1) to find the genotypes of the following hypothetical phenotypic information: a. Within a particular population, you observe that 450 individuals have freckles (dominant, F) and 550 do not have freckles (recessive, f). b. Homozygous dominant (frequency) ______(A)_________ c. Heterozygous (frequency) ______(B)_____________ d. Homozygous recessive (frequency) _______(C)____________
1. According to the Hardy-Weinberg theorem, p + q = 1 and p2 + 2pq +q2...
1. According to the Hardy-Weinberg theorem, p + q = 1 and p2 + 2pq +q2 = 1. What does each of these formulas mean (how are they derived)?
I've tried 0.16, 0.48, 0.36 and 32, 96, 72 I have 2 trials left, please help....
I've tried 0.16, 0.48, 0.36
and 32, 96, 72
I have 2 trials left, please help.
Here's a hint: Hint 2. How to calculate the
expected frequencies of a different example population Consider an
example population of individuals that have two alleles for a
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2pq+q? 1 If the dominant allele frequency is 0.8, what percent of the population will be...
2pq+q? 1 If the dominant allele frequency is 0.8, what percent of the population will be homozygous In the Hardy Weinberg equation, p recessive? Ο Ο Ο Ο Ο
Question 13 2 pts The Hardy-Weinberg equation is p+2pq+q?-1. In a case where one allele represented...
Question 13 2 pts The Hardy-Weinberg equation is p+2pq+q?-1. In a case where one allele represented by pis completely dominant to the other allele represented by q, the term 2pa represents the heterozygotes hemizygotes homozygous for the recessive trait homozygous for the dominant trait Question 14 2 pts If q=2. then 2pg equals 0.16 O 0.8 O 0.32 0 0.04
For two alleles at frequencies p and q in a population at Hardy-Weinberg equilibrium, which of...
For two alleles at frequencies p and q in a population at Hardy-Weinberg equilibrium, which of the following statements is most likely to be TRUE? A. When p = q, all individuals in the population are heterozygous. B. When p = q, no individuals in the population are heterozygous. C. When p = 1, half of the individuals in the population are heterozygous. D. When p = 0, all individuals in the population are heterozygous E. When p = 0.5,...
In the figure, p is the frequency of allele A, and is the frequency of allele...
In the figure, p is the frequency of allele A, and is the frequency of allele a in a diploid population. Assuming no differences in fitness, pand should also be the frequencies of A gametes and a gametes produced by the adults. The A and a gametes combine during fertilization to produce diploid zygotes. If mating is random and the population is large, the proportion of offspring with each of three genotypes (AA, Aa, and aa) can be predicted using...
You are studying a population of wolves and you find 5% of the alleles at a...
You are studying a population of wolves and you find 5% of the alleles at a specific coat color locus in your population are recessive. If you were to consider this information in the context of the Hardy- Weinberg theorm, the 5% you have been given represents: Oq 2pq q^2 O p^2 + 2pq O allele frequency Question 2 1 pts You are studying a population of armadillos and you find 34% of the population is homozygous for a recessive...
I've tried 0.16, 0.48, 0.36
and 32, 96, 72
I have 2 trials left, please help.
Here's a hint: Hint 2. How to calculate the
expected frequencies of a different example population Consider an
example population of individuals that have two alleles for a
specific locus, AB and AC. In the population, 70% (0.7) of the
alleles are AB, and 30% (0.3) of the alleles are AC. The expected
frequencies of each genotype can be calculated using the equation
for...
2.3 Problem 3 The Hardy-Weinberg equation is useful for predicting the percent of a hu- man population that may be heterozygous carriers of recessive alleles for certain genetic diseases. Phenylketonuria (PKU) is a human metabolic dis- order that results in mental retardation if it is untreated in infancy. In the United States, one out of approximately 10.000 babies is born with the disor- der. Approximately what percent of the population are heterozygous carriers of the recessive PKU allele? If you...
2pq+q? 1 If the dominant allele frequency is 0.8, what percent of the population will be homozygous In the Hardy Weinberg equation, p recessive? Ο Ο Ο Ο Ο
Question 13 2 pts The Hardy-Weinberg equation is p+2pq+q?-1. In a case where one allele represented by pis completely dominant to the other allele represented by q, the term 2pa represents the heterozygotes hemizygotes homozygous for the recessive trait homozygous for the dominant trait Question 14 2 pts If q=2. then 2pg equals 0.16 O 0.8 O 0.32 0 0.04
In the figure, p is the frequency of allele A, and is the frequency of allele a in a diploid population. Assuming no differences in fitness, pand should also be the frequencies of A gametes and a gametes produced by the adults. The A and a gametes combine during fertilization to produce diploid zygotes. If mating is random and the population is large, the proportion of offspring with each of three genotypes (AA, Aa, and aa) can be predicted using...
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