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2pq+q? 1 If the dominant allele frequency is 0.8, what percent of the population will be homozygous In the Hardy Weinberg equ
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Answer #1

Answer: 0.04

Explanation:

Dominant allele frequency = p = 0.8

Recessive allele frequency = q = 0.2 (as p+q=1)

Frequency of recessive phenotype = qq = 0.2 * 0.2 = 0.04

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