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4. Referring to Figure 26.0, a magnetic circuit core is made of stalloy and has and...
QUESTION 2 a) Given a magnetic circuit as shown in Figure Q2 where its core is cast steel. The center limb has a cross-sectional area of 800mm2 and the other side limbs have a cross sectional area of 500mm2. The effective air gap length, lac is Imm, core length, loc= 150mm . ladb = laeb = 340mm . A coil of 400 turns is wound on the center limb. Neglect any magnetic leakage and fringing effect. i. Draw the equivalent...
1. Consider the toroidal core shown in the Figure. Find the current needed to produce a flux density of BFe = 1.2[T] in the following two case - No air gap - With a 2-mm air gap Let N = 100 and u = 4000 for the iron. The iron cross-sectional area, A = 4cm.
15 marks] B. A toroidal core with a mean diameter of 200 mm and a cross-sectional area of 800 mm has an air gap of length 1.1 mm cut in it Fringing and leakage of flux around the air gap may be neglected (i) Determine the current required in a coil of 1100 turns to produce a flux density of 1 T The relative permeability , of the core material (iron) may be assumed to be 3000 for this level...
6) Figure Q4(b) shows a coils of 200 turns. The coil is uniformly wound around a wooden ring with a mean circumference of 600mm and cross-section area of 500mm%. The current flowing into the call is 4A. (Permeability of free space fle = 4ex 10' Hm'. Calculate: L. the magnetic field strength (2 marks) flux density (1 marks) total flux (1 marks) turn I meter Figure Q4 (b) A magnetic circuit made of cast steel is arranged as in Figure...
94 Exercise :4.A square magnetic core Figure :4. has four 0.5 mm air gaps. The core material has a relative permeability of us = 800 and a coil of 1400 turns is wound around it. The core has a square cross-sectional area of dimensions 4 cm and a magnetic path length (including the air gaps) is 20 cm. A = 4 cm 2 N = 1400 4 Air gaps = 0.5 mm each Figure : 4. = 20 cm including...
b) A portion of a solenoid is shown as in Figure Q3(b). The magnetic circuit comprises of cast iron yoke, sheet steel plunger, cast steel plunger and air gaps. The yoke and plunger have a cross section area of 4.8x10 m´and 4.5x10m respectively. A coil is wound on the center of the yoke. The effective length of the cast iron yake, sheet steel plunger and cast steel plunger are la = 0.25 m; 4 = 0.12 m and l =...
can i get the right solution please Question 1: (25 marks) A ring of steel has an external diameter of 24cm and a square cross section of 3cm by 3cm, as she m, as shown in Figure 1. A gap of 3mm exists on the ring. A copper bar of 18cm x 3cm x 3cm is fitted inside Titted inside and across the ring with negligible gap. Account for fringing by using the effective area of the air approximated by:...
please help asap ,I'll rate MAGNETISATION CURVES 1.6 1.6 ded 1.4 1.4 1.2 -1.2 -1.0 Belchalk steel Magnetic flux density, B, Tesla 0.8 0.8 l'niversity of the Witwatersrand, Johanaburg Mohool of Electrical Information Engineering 0.6 -0.6 0.4 0.4 0.2 0.2 200 400 600 1400 1600 1800 2000 800 1000 1200 Magnetic field Intensity, H, A/m JF2001 Question 2 of 15 1 Points Click to see additional instructions If Bc = 1.0 T for silicon steel, then Hc = A-t/m. [Select...