I need a test bench code for this module in verilog.
I need a test bench code for this module in verilog. Verilog Code module part6 (А.В.us,G,E,L);...
I need the following in verilog. Attached is also the test bench. CODE // Design a circuit that divides a 4-bit signed binary number (in) // by 3 to produce a 3-bit signed binary number (out). Note that // integer division rounds toward zero for both positive and negative // numbers (e.g., -5/3 is -1). module sdiv3(out, in); output [2:0] out; input [3:0] in; endmodule // sdiv3 TEST BENCH module test; // these are inputs to "circuit under test" reg...
Write a test bench to thoroughly test the Verilog module dff_fe_asyn_h. below is the module ddff_fe_asyn_h.code Simulate the circuit using ISim and analyze the resulting waveform. Verilog Code for dff_fe_asyn_h is mentioned below:- //DFF module with asynchronous active high reset with negative edge trigger with clock module dff_fe_asyn_h ( input clock, // Clock Input input reset, // Reset Input input data_in, // Input Data output reg data_out // Output Data ); always @ (negedge clock or posedge reset) // triggers...
7. Which of the following Verilog code segments will generate errors when compiled? A. module demo output reg F, input a): ire b; reg c assign b-c; initial begin end endmodule module demo5 output reg F, input reg a); ire b reg c assign bC; initial begin end C. module demooutput reg F, input wire a ire b reg c assign b c; initial begin F c& b; end D. O both A) and C) E. O none will generate...
Draw the circuit corresponding to the Verilog module below. (Do not attempt to simplify the circuit.) module Circuit A (e, F, G, H); parameter n= 3; input [n-1:0] F, G; input e; output reg [n-1:0] H; integer k; always @ (e, F, G) begin for (k=0; k<n; k=k+1) H[k] = (e | F[k]) & G[k]; end endmodule
3. (10 Points) RTL Combinational Circuit Design a Draw the schematic for the Verilog code given below: module abc (a, b, c, d, si, s0); input 31, 30; output a, b, c,d; not (51_, 51), (50_, 0); and (a, s1_, SO_); and (b, s1_, 0); and (c, sl, s0_); and (d, sl, s0); endmodule b. Draw the schematic for the Verilog code given below: module Always_Code input a, b, c, output reg F ); always @(a, b, c) begin F...
I need help writing a test bench for the following Verilog code module CU(IE, WE, WA, RAE, RAA, RBE, RBA, ALU, SH, OE, start, clk, reset, Ng5); //nG5 denotes (N>5); input start, clk, reset; output IE, WE, RAE, RBE, OE; output [1:0] WA, RAA, RBA, SH; output [2:0] ALU; input wire Ng5; reg [1:0] state; reg [1:0] nextstate; parameter S0 = 3'b000; parameter S1 = 3'b001;...
Using Verilog, write a simulation code that shows the function g(w, x, y, z) = wxyz + w’x’y’z+w’x’yz’+w’xy’z’+wx’y’z’ using a 4 to 16 decoder that is built with two 3 to 8 decoders. The 3 to 8 source code I'm using is: module Dec3to8( input[2:0] A, input E, output[7:0] D ); assign D[0] = E & ~A[2] & ~A[1] & ~A[0]; assign D[1] = E & ~A[2] & ~A[1] & A[0]; assign D[2]...
help me to finish the verilog code and test bench Part 2: Sequence Counter Design the sequence counter using Xilinx Vivado. Consider the required number of D flip-flops(4). A sample VERILOG source file is as shown: module Seq_COUNT( ??? clock, ??? wire [?:?] D, ??? ??? [?:?] out ); always @ (??? ???) ??? // 3 bit Sequence Given is 0 2 4 6 1 3 5 7 out[N-1] <= some expression;...
(15 pts) 1. Draw a logic diagram for the Verilog code. module Seq_Ckt ( CLK, PR, sel, Q); input CLK, PR, sel; output reg [2:0] Q; reg [2:0] y; assign Q = y; always @ (posedge PR, posedge CLK) begin if (PR== 1) then y <= 3'b111; else if (sel) begin y[2] <= y[1] ^ y[0]; y[1] <= y[2]; y[1]; end else y[2] <= y[2] ; y[1] <= y[1]; y[0]; y[O] <= y[0] <= end endmodule
Given the following verilog code, draw the corresponding state diagram for it. module mysterious (input reset, clk, TB, TA, output reg [1:0] LB, LA); reg [1:0] cstate, nstate; parameter S0 = 2'b00; parameter S1 = 2'b01; parameter S2 = 2'b10; parameter S3 = 2'b11; parameter grn = 2'b00; parameter ylw = 2'b01; parameter rd = 2'b10; // state register always @ (posedge clk, posedge reset) begin if (reset) cstate <= S0; else cstate <= nstate; end // next state logic...