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QUESTION 1 OF 10 Please read Chapter 1 of the Lab Manual and the relevant Power Point lecture in detail, and answer the follo

Suppose that in an experiment you observed 113 cells in interphase, 24 cells in prophase, 9 cells in metaphase, 12 cells in anaphase, and 3 cells in telophase stages. If the complete cell cycle (i.e. G1+S+G2+mitosis; see Figure 1-2 of the Lab Manual) requires 24 hours, calculate the average duration of each stage in the cycle. Show all calculations.

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Answer #1

Prophase index= (P/(Total number of cells))*100

where, P is the number of cells in prophase

Prophase index= (24/(113+24+9+12+3)) x 100

= 14.9%

So the 14.9 % of the total cell cycle belongs to prophase

Duration of prophase= (14.9/100) x 24 hours

= 3.58 hours

Metaphase index= (M/(Total number of cells))*100

where, M is the number of cells in metaphase

Metaphase index= (9/(113+24+9+12+3)) x 100

= 5.59%

So the 5.59 % of the total cell cycle belongs to Metaphase

Duration of metaphase= (5.59/100) x 24 hours

= 1.34 hours

Anaphase index= (A/(Total number of cells))*100

where, A is the number of cells in Anaphase

Anaphase index= (12/(113+24+9+12+3)) x 100

= 7.45%

So the 7.45 % of the total cell cycle belongs to Anaphase

Duration of anaphase= (7.45/100) x 24 hours

= 1.79 hours

Telophase index= (T/(Total number of cells))*100

where, T is the number of cells in telophase

Telophase index= (3/(113+24+9+12+3)) x 100

= 1.86%

So the 1.86% % of the total cell cycle belongs to telophase

Duration of telophase= (1.86/100) x 24 hours

= 0.45 hours

So the total duration of mitosis is = (3.58+1.34+1.79+0.45)

= 7.16 hours

Therefore the time the cell spends in Interphase= (Total duration of cell cycle - Time spent in mitosis)

= (24 - 7.16)

= 16.84 hours

  

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