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Question 3 [10 points] Find a formula in terms of k for the entries of Ak, where A is the Hermitian matrix below A= Ak= -1938

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solution:- The characteristic equation of A is 7 + 2A + 486 - 0 7 sint six-486=0 37 +1-6=0 The eigen values of A are = +31-20al all so, the eigen vector corresponding to had are ada-3 k (4) 1512-41) 9.196 - go ija - #44= 3y > Smilarly g / **(844)) na

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