Question

November 6, 2019 3. As it turns out, a pool of water will also produce an image of a submerged object. Thus, we talk about "apparent depth" of an object. You stand at the edge of a pool with your eyes 2m about the level of the water. You see a stick that you know is 3m long at the bottom of the pool. It appears to you that the stick is 1m below the surface of the water. You want to know what the actual depth of the water. (1 square=1m) a. What is the angle of refraction of the light as it leaves the pool in this case, O 1)? b. Working backward, what is the angle of incidence of the light as it leaves the pool in this case, 2)? c. Using the diagram below (and trigonometry), what is the actual depth of the object? d. What is the ratio of the depths? e. Can you suggest a relationship between apparent depth and actual depth?

Answer 1

tan 0,= 2 2 = 1 0 = 45 SU Snell's low nisino, che sino 1x Sin45 = 4 sind, 1, 2 refrective index of air na referent index of water N=1 ; M2 24/3. Sing = YE Os oito for single toma = tansin 13 zm Im t am →