Homework Answers
1. Number of individuals Percent of population
AA 10 0.2%
AS 40 0.8%
SS 0 0%
Total 50
Creating Generation 2
|
Number |
Couple |
Number of children |
1 |
2 |
3 |
4 |
5 |
6 |
|
1 |
AA & AS |
4 |
AA |
AS |
AA |
AA |
||
|
2 |
AS & AA |
4 |
AA |
AS |
AA |
AS |
||
|
3 |
AA &AS |
4 |
AA |
AS |
AS |
AS |
||
|
4 |
AS& AS |
4 |
AA |
AS |
AS |
SS |
||
|
5 |
AS & SS |
3 |
AS |
SS |
AS |
SS |
||
|
6 |
AA & AS |
1 |
AA |
|||||
|
7 |
SS & AA |
3 |
AA |
SS |
SS |
|||
|
8 |
AA & SS |
4 |
AS |
AS |
AS |
AS |
||
|
9 |
AS & AS |
2 |
AA |
SS |
||||
|
10 |
AA & AA |
2 |
AA |
AA |
||||
|
11 |
SS & AS |
4 |
AS |
SS |
AS |
SS |
||
|
12 |
SS & SS |
3 |
SS |
SS |
SS |
|||
|
13 |
AA & AS |
3 |
AA |
AS |
AA |
|||
|
14 |
AS & SS |
1 |
AS |
|||||
|
15 |
AA & SS |
2 |
AS |
AS |
||||
|
16 |
AS & AS |
2 |
AA |
AS |
||||
|
17 |
AA & SS |
4 |
AS |
AS |
AS |
AS |
||
|
18 |
AS & SS |
3 |
AS |
SS |
SS |
|||
|
19 |
AA & AA |
2 |
AA |
AA |
||||
|
20 |
AA & AS |
AS |
AS |
AA |
AS |
3. Total number of AA genotypes = 18
Total number of AS genotypes = 29
Total number of SS genotypes = 13
Total number of individuals = 60
4 a. Total number of individuals before effects of sickle cell anemia and malaria = 14.4
Subtract SS individuals- 13
Subtract malaria victims - 3.6 = 4
Total number of remaining individuals comprising generation 2 = 60-17 = 43
b. Left AA = 14.4
Percentage of total remaining individuals = 14.4/43 = 33.48%
AS = 29
Percentage of total remaining individuals = 29/43 = 67.44%
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