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1. Determine the cracking moment for the following sections if fe'is 4000 psi. 30 in. 18...
Compare the cracking moment based on the gross section properties and the transformed section properties with...
Compare the cracking moment based on the gross section properties and the transformed section properties with four No. 11 (No. 36) bars in Figure P4.1a based on a concrete tensile capacity of 7.5 FIGURE P4.1 12-1 2-2 24 typ 2-6 8-1 (d)E-3000 psl (a)E-4000 psi (c)-6000 ps (D)E-5000 ps
Compare the cracking moment based on the gross section properties and the transformed section properties with four No. 11 (No. 36) bars in Figure P4.1a based on a concrete tensile capacity...
4. For the beam shown below,fe' = 4000 psi and fy = 60,000 psi. (20 points)...
4. For the beam shown below,fe' = 4000 psi and fy = 60,000 psi. (20 points) (a) Compute the effective flange width at midspan. 911-6 in (a) Beam section and distance to adjacent beams Support (negative bending) Midspan positive bending) 7 No. 7 bars IIT 3 No. 8 plus 2 No. 7 bars at midspan 22 2 No. 8 bars at ends (b) Beam span supported by 18-in. wide columns (b) Compute Mn for the positive and negative-moment regions and...
Cracking Moment (Uncracked Concrete Stage) Problem 1) Problem 2.6 (page 55, McCormac and Brown, gth Ed.)...
Cracking Moment (Uncracked Concrete Stage) Problem 1) Problem 2.6 (page 55, McCormac and Brown, gth Ed.) Note: Modify the total depth of the beam from 24" to 26" and the depth of the steel rebars from 21" to 23". Transformed Area Method (Concrete Cracked- Elastic Stresses Stage) Problem 2) Problem 2.13 (page 56, McCormac and Brown, 8th Ed.) Note: Make the following changes: Change fe to 5 ksi use the values and dimensions shown in the figure below 1) 2)...
Problem 5. Determine the nominal or theoretical moment capacity Mn of beam iffy = 60,000 psi...
Problem 5. Determine the nominal or theoretical moment capacity Mn of beam iffy = 60,000 psi and fc' = 4000 psi. 3 in 3 in... 3 in.3 in. inli 18 in
1) Assuming Mcr = 125 k-ft, Ig = 47,250 in4 , Icr = 24,000 in3 , the moment of inertia for calculating a deflection cor...
1) Assuming Mcr = 125 k-ft, Ig = 47,250 in4 , Icr = 24,000 in3 ,
the moment of inertia for calculating a deflection corresponding to
Ma = 200 k-ft, is most nearly:
A. 47,250 in4
B. 24, 000 in4
C. 30,000 in 4
D. 38,500 in 4
E. Other (specify) (g)
2) Assuming ΔD = 0.5 in.; ΔLL = 0.3 in., and ξ = 1.5, the total
deflection of the beam is most nearly:
A. 0.8 in
B. 1.3...
For the beam shown use f-3000 psi and fy 60000 psi. 1- Compute the effective flange...
For the beam shown use f-3000 psi and fy 60000 psi. 1- Compute the effective flange width 2- Compute фМ, for the positive and negative moment regions and check ACI requirements for both sections. At the support, the bottom bars are in one layer and at mid-span, the # 8 bars are in the bottom layer and the # 7 bars are in a second layer. Assume 2.5 in concrete cover (from outside face of concrete to the center of...
NOTE Vn(min)= 12.8k Vn(Max)= 81.9k 2) Design the stirrups for the beam using f'4000 psi concrete and # 3 Grade 60 s...
NOTE
Vn(min)= 12.8k
Vn(Max)= 81.9k
2) Design the stirrups for the beam using f'4000 psi concrete and # 3 Grade 60 stirrups. a) Determine if and where no stirrups can be used in the beam. b) Provide 3 "zones" of stirrups: maximum permissible spacing near midspan, tightest spacing near the support and a transition zone 12 in f4000 psi d 16 in 24 ft #3 stirrups Normal weight concrete 3/4 in. max. aggregate 1.5 in. clear cover 2.69 in 3...
pls show work 2. Find the effective moment of inertia for the following concrete sections (f....
pls show work
2. Find the effective moment of inertia for the following concrete sections (f. = 4000 psi) when cracked moment to applied moment ratio is (a) 0.9 (b) 0.7 and (c) 0.5. Note: values are not from an actual beam. Calculate the applied moment if the beam span is 8 ft and (a) the central point load is 8 kip and (b) a UDL of 1 kip/ft is applied. Calculate the deflection due to a point load of...
Question 1: Calculate Ig and Icr for cross sections (a) and (b) shown in Figure (1). Given: fc=4,000 psi, Normal-Weight...
Question 1: Calculate Ig and Icr for cross sections (a) and (b) shown in Figure (1). Given: fc=4,000 psi, Normal-Weight Concrete fy=60,000 psi, and Es 29 X 105 psi. 30 in. (762 mm) 3 in. 3 No. 10 3 No, 9 2을 in. 12 in. (304,8 mm) in. -10 in.- (b) (a) 15 in. (wu (533.4 mm)
Question 1: Calculate Ig and Icr for cross sections (a) and (b) shown in Figure (1). Given: fc=4,000 psi, Normal-Weight Concrete fy=60,000 psi,...
Question 1 20 pts Determine Oplfor the following element in psi (to the nearest 0.01 psi)...
Question 1 20 pts Determine Oplfor the following element in psi (to the nearest 0.01 psi) 0,4 psi 16 psi Try 24 psi Next > 30 4 + 2 $ 4 % 5 A 6 3 & 7 B W E R T Y S D F H J к
Compare the cracking moment based on the gross section properties and the transformed section properties with four No. 11 (No. 36) bars in Figure P4.1a based on a concrete tensile capacity of 7.5 FIGURE P4.1 12-1 2-2 24 typ 2-6 8-1 (d)E-3000 psl (a)E-4000 psi (c)-6000 ps (D)E-5000 ps
Compare the cracking moment based on the gross section properties and the transformed section properties with four No. 11 (No. 36) bars in Figure P4.1a based on a concrete tensile capacity...
4. For the beam shown below,fe' = 4000 psi and fy = 60,000 psi. (20 points) (a) Compute the effective flange width at midspan. 911-6 in (a) Beam section and distance to adjacent beams Support (negative bending) Midspan positive bending) 7 No. 7 bars IIT 3 No. 8 plus 2 No. 7 bars at midspan 22 2 No. 8 bars at ends (b) Beam span supported by 18-in. wide columns (b) Compute Mn for the positive and negative-moment regions and...
Cracking Moment (Uncracked Concrete Stage) Problem 1) Problem 2.6 (page 55, McCormac and Brown, gth Ed.) Note: Modify the total depth of the beam from 24" to 26" and the depth of the steel rebars from 21" to 23". Transformed Area Method (Concrete Cracked- Elastic Stresses Stage) Problem 2) Problem 2.13 (page 56, McCormac and Brown, 8th Ed.) Note: Make the following changes: Change fe to 5 ksi use the values and dimensions shown in the figure below 1) 2)...
Problem 5. Determine the nominal or theoretical moment capacity Mn of beam iffy = 60,000 psi and fc' = 4000 psi. 3 in 3 in... 3 in.3 in. inli 18 in
1) Assuming Mcr = 125 k-ft, Ig = 47,250 in4 , Icr = 24,000 in3 ,
the moment of inertia for calculating a deflection corresponding to
Ma = 200 k-ft, is most nearly:
A. 47,250 in4
B. 24, 000 in4
C. 30,000 in 4
D. 38,500 in 4
E. Other (specify) (g)
2) Assuming ΔD = 0.5 in.; ΔLL = 0.3 in., and ξ = 1.5, the total
deflection of the beam is most nearly:
A. 0.8 in
B. 1.3...
For the beam shown use f-3000 psi and fy 60000 psi. 1- Compute the effective flange width 2- Compute фМ, for the positive and negative moment regions and check ACI requirements for both sections. At the support, the bottom bars are in one layer and at mid-span, the # 8 bars are in the bottom layer and the # 7 bars are in a second layer. Assume 2.5 in concrete cover (from outside face of concrete to the center of...
NOTE
Vn(min)= 12.8k
Vn(Max)= 81.9k
2) Design the stirrups for the beam using f'4000 psi concrete and # 3 Grade 60 stirrups. a) Determine if and where no stirrups can be used in the beam. b) Provide 3 "zones" of stirrups: maximum permissible spacing near midspan, tightest spacing near the support and a transition zone 12 in f4000 psi d 16 in 24 ft #3 stirrups Normal weight concrete 3/4 in. max. aggregate 1.5 in. clear cover 2.69 in 3...
pls show work
2. Find the effective moment of inertia for the following concrete sections (f. = 4000 psi) when cracked moment to applied moment ratio is (a) 0.9 (b) 0.7 and (c) 0.5. Note: values are not from an actual beam. Calculate the applied moment if the beam span is 8 ft and (a) the central point load is 8 kip and (b) a UDL of 1 kip/ft is applied. Calculate the deflection due to a point load of...
Question 1: Calculate Ig and Icr for cross sections (a) and (b) shown in Figure (1). Given: fc=4,000 psi, Normal-Weight Concrete fy=60,000 psi, and Es 29 X 105 psi. 30 in. (762 mm) 3 in. 3 No. 10 3 No, 9 2을 in. 12 in. (304,8 mm) in. -10 in.- (b) (a) 15 in. (wu (533.4 mm)
Question 1: Calculate Ig and Icr for cross sections (a) and (b) shown in Figure (1). Given: fc=4,000 psi, Normal-Weight Concrete fy=60,000 psi,...
Question 1 20 pts Determine Oplfor the following element in psi (to the nearest 0.01 psi) 0,4 psi 16 psi Try 24 psi Next > 30 4 + 2 $ 4 % 5 A 6 3 & 7 B W E R T Y S D F H J к
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