Given that V. - 5 V in the network in the figure, find Vs. +-WSW 51...
Find Vs in the network in the figure below if V-420° v. 1 2 ?? 2862 VI 2? 2? (a) Find the real part of the voltage. (b) Find the imaginary part of the voltage.
Chapter 5, Problem 5.010 (Circuit Solution)
In the network in the figure below, find using
superposition.
We were unable to transcribe this imageChapter 5, Problem 5.010 (Circuit Solution) In the network in the figure below, find I, using superposition. 5kn 6ko 36ko 1 Va= 12 V la = 6 MA I. with only ve turned on = I. with only Iturned on =
Chapter 5, Problem 5.068 Use Thévenin's theorem to find V. in the circuit in the figure below. Break the network just to the right of the vertical 7k Ohm resistor containing Ix. 7 ko 3k 6 x 6ko 7ko v. Vth = Rth = Vo =
3) Given that Vo 4 V in the network in the circuit below, find Vs. 2 k12 6 V 3 k1 12kΩ 2mA
Given Vo in the network in the figure, find IA 12 V 2 mA the tolerance is +/-100
Find Vx in the network
shown in the given figure, where P = 8<50° V. Please
report your answer so the magnitude is positive and all angles are
in the range of negative 180 degrees to positive 180 degrees.
Find V, in the network shown in the given figure, where P = 8/50° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. j1Ω 2...
T1.4. The circuit shown in Figure T1.4 has Vs = 12 V, v 2 =4 V, and R 1 =42 Figure T1.4 a. Find the values of a. v1; b. i c. R2 T1.5. We are given Vs =15 V, R=10 , and a= 0.3 S for the circuit of Figure T1.5. Find the value of the current i sc flowing through the short circuit. o ar, a=0.35 Figure T1.5
Find Vo in the network in the figure using
loop analysis.
Find V. in the network in the figure using loop analysis. 6 ν(Ε) (14 mA 1 ΚΩ T + VO - –ΛΛΑ 2 ΚΩ 32 ΚΩ 31 ΚΩ ( 3 mA
For the op amp circuit in the given figure, suppose vs 24u(t) V. Find v(t) for t> 0. 100 kΩ 100 kΩ The voltage v(t) = Hints References eBook & Resources
Find Vy in the network shown in the given figure, where P = 10240° V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. j1Ω 2Ω 2Ω + V P j4 Ω j4 Ω -j1Ω 2/0° A The value of VX V.