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What is the usable free energy (per mol) for transduction when NADH oxidizes and 1/2 02 reduces? Note the following standard reduction potentials NAD+ + H+ + 2 e-? NADH ED/ =-0.32 V ½o2 + 2H+ + 2 e-?H2O Eo, _ +0.82 V Choose one: A. -55.0 kJ/mol of NADH oxidized B. -110 kJ/mol of NADH oxidized C. -440 kJ/mol of NADH oxidized D. -220 kJ/mol of NADH oxidized

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Answer #1

E° cell=E°cathode - E°anode=+0.82-(-0.32)V=1.14V

Free energy=-nFE°cell

n=2(number of electrons transferred)

F=96500

Putting the values, Free energy=-2(96500)(1.14)=-220.020KJ/mole

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