Is the process in control? Discuss by constructing the mean and range charts.
Homework Answers
n (Sample size) = 5
A2 = 0.58, D3 = 0, D4 = 2.11
Mean = Average of observation for each sample
Range = Maximum value - Minimum value
| Sample | 1 | 2 | 3 | 4 | 5 | Mean | Range |
| 1 | 10.1 | 10.6 | 9.8 | 9.9 | 10.9 | 10.26 | 1.1 |
| 2 | 9.7 | 9.5 | 10.3 | 9.9 | 10.5 | 9.98 | 1 |
| 3 | 10.1 | 10.7 | 9.2 | 10 | 10.1 | 10.02 | 1.5 |
| 4 | 9.9 | 9.8 | 10.5 | 10.4 | 10.1 | 10.14 | 0.7 |
| 5 | 10.4 | 10.1 | 10.9 | 9.9 | 10.3 | 10.32 | 1 |
X-bar = Average of Mean value = (10.26+9.98+10.02+10.14+10.32)/5 = 10.14
R-bar = Average of Range value = (1.1+1+1.5+0.7+1)/5 = 1.06
Mean chart:
UCL = X-bar + A2*R-bar = 10.14 + 0.58*1.06 = 10.75
LCL = X-bar - A2*R-bar = 10.14 - 0.58*1.06 = 9.53
Range cahrt:
UCL = D4*R-bar = 2.11*1.06 = 2.24
LCL = D3*R-bar = 0*1.06 = 0
Process is not in control as few values are out of range of Mean chart. Example: Sample 1 Observation 5, Sample 3 Observation 3 etc.
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Is the process in control? Discuss by constructing the mean and
range charts.
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