Question

JAVA:

Excerpt B.A:

Complete the implementation of the following method. The purpose of this method is to return true if and only if all the elements in the array are x. In other words, all elements in the array are the value x (replace -a- with right answer).

public static -a- allSame(int[] nums, int x){
for (int i = 0; i < -a-; i++){
if (nums[i] -a- x){
return -a-;
}
}
return -a-

}

Excerpt B.B: What is printed on the code below after calling myMethod2("UTEPMINERS"); - also, this code may need to be fixed:
public static void myMethod22(String str){
if (str length() == 0){
return;
}
else {
myMethod22(str.substring(1, str.length() - 1));
System.out.print(str.charAt(0));
}
}

Except B.C:

Complete the implementation of the method getNumVowels. This method receives a string as input and returns the number of vowels (a, e, i, o, u) in the string (replace -a- with right answer).

public static -a- getNumVowels (-a- s){
int count = -a-;
for (int i = 0; i < -a-; i++)
{
switch (-a-) {
case 'a':
case 'e':
case 'i':
case 'o':
case 'u':
-a-
}
}
return -a-;
}
  

Answer 1

Excerpt B.A:

   public static boolean allSame(int[] nums, int x){
for (int i = 0; i < nums.length; i++){
if (nums[i] != x){
return false;
}
}
return true;
  
}

Excerpt B.B:

Output of : myMethod2("UTEPMINERS")

Output : SRENIMPETU // as this is the code to print string in reverse

CODE

public static void myMethod22(String str){
if (str.length() == 0){
return;
}
else {
myMethod22(str.substring(1, str.length())); // str.substring(1, str.length()) instead of str.substring(1, str.length()-1)
System.out.print(str.charAt(0));
}
}

Excerpt B.C:

public static int getNumVowels (String s){
int count = 0;
for (int i = 0; i < s.length(); i++)
{
char ch = s.charAt(i);
switch (ch)
{
case 'a':
case 'e':
case 'i':
case 'o':
case 'u':
count++;
}
}
return count;
}