matlab part: a
clc;
clear all;
close all;
s=tf('s');
g=8/(s*(s+8)^2);% plant
margin(g);grid
legend('bode of plant')
figure
rlocus(g);
legend('root locus of plant')
matlab part b)
clc;
clear all;
close all;
s=tf('s');
k=40;
t95=0.1528;% 95% of delay time
t105=0.1688;% 105% of delaytime
gc1=exp(-t95*s);
gc2=exp(-t105*s);
g=8/(s*(s+8)^2);% plant
step(feedback(k*g*gc1,1));grid
legend('step response with 95% td')
figure
step(feedback(k*g*gc2,1));grid
legend('step response with 105% td')
matlab part c)
clc;
clear all;
close all;
s=tf('s');
k95=9.8338;
k105=10.869;
gc=exp(-s);
g=8/(s*(s+8)^2);% plant
step(feedback(k95*g*gc,1));grid
legend('step response with 95% k')
figure
step(feedback(k105*g*gc,1));grid
legend('step response with 105% k')
Consider the following closed-loop system, in which the plant model is P(s) = elave R()2-CO POTY()...
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