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Air within the tank is at an absolute pressure of 680 kPa and a temperature of 70°C. The tank has an interior volume of 2.35 m3. The gas constant for air is  R= 286.9 J/[kg·K] (Figure 1) 


Part A

Determine the weight of the air inside the tank 

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Answer #1

z 680 X103 pa Pi= 680kpa 2. R = 286-9 /k9 V= 2.35 m3 T=70°C = 70 +273 = 343 k 1) by gas law D Pv= mRT - mx 2869 x 343 =680X10g

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