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T =1050 K P.950 kPa m-5k/s Q=12 kW Question 1 150 Points) Combustion gases that we can assume to be air enter a gas turbine a
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sW. T=1050K P1 = 950 kPa - m= 5 kg/8 Qrej = 42 kW T2=850k Pi= 300 kPa To = 25 C +273 = 298k Po=100 kPa To > Applying energy b- 52-6, 7- 1.005 in (8503) - 0.287 In 300) S2-5, = 0.11845 kJ/kg k S-62 = -0.11845 kJ/kgk Now, put (5,-52) = -0.11845 KI To a

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