Homework Answers
Answer:
Expected double crossover offsprings = 5
Interference = 0.4
Explanation:
A----8mu----B----12mu----C
Distance between genes (mu) = Recombination frequency (%)
Expected double crossover frequency = (RF between A&B) (RF between B&C)
= 8% x 12%
= 0.08 x 0.12
= 0096
Number of double crossover offsprings = 0.0096*500 = 4.8 or 5
Coefficient of Coincidence (COC) = Observed double crossovers / Expected double crossovers
= 3/5 = 0.6
Interference (I)= 1 – COC
I = 1- 0.6 = 0.4
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