12) A certain standardized test has scores which range from 0 to 500, with decimal scores possible. Scores on the exam are normally distributed with a mean of 306 and a standard deviation of 43. Find the percentile P67 for the scores of students taking the exam.
Round your answer to 2 decimal places.
Given that,
mean = = 306
standard deviation = =43
Using standard normal table,
P(Z < z) = 67%
=(Z < z) = 0.67
= P(Z < 0.44 ) = 0.67
z = 0.44
Using z-score formula
x = z +
x = 0.44 *43+306
x = 324.92
12) A certain standardized test has scores which range from 0 to 500, with decimal scores...
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