Question

Examine the function below and answer the following questions.

int gLobal = 25; // declared outside function

int func( int X, char *Y, BYTE Z )

{

int a;

char b[] = “The lazy dog ate the red fox before jumping over it.”

char *c;

c = (char *) malloc(512K);

a = b[0];

return a;

}

--

b. How many bytes used on the stack for ‘Z’.

c. How many 4K pages of physical memory are needed for the above malloc?

d. How many bytes are used on the stack for the local variables in this function?

Answer 1

b)

Since Z is of type 'BYTE', 1 byte of memory is allocated on the stack for Z

c)

Using malloc we are allocating a memory of 512K in heap/main memory.
So number of physical memory pages = 512K/4K = 128

d)

The local variables here are

1. int a; => 4 bytes(number of bytes varies for different platforms)
2. char b[] = "The lazy dog ate the red fox before jumping over it." => 52 bytes (since each charactter is of size 1 byte)

3. char *c; => it needs 4 bytes of memory since it is a character pointer
4. int X => 4 bytes
5. char *Y => 4 byte
6. BYTE Z => 1 byte

Hence, 69 bytes are used for the local variables in this function

PLEASE UPVOTE IF THE ANSWER WAS HELPFUL