Question

A stone with a mass of 3.20 kg is moving with velocity (6.20 - 2.209) m/s. (HINT: v2 - v.v.) (a) What is the stones kinetic

0 0
Add a comment Improve this question Transcribed image text
Answer #1

m = 3.2kg V = 16.20122.203 ) mis - 2 @ Ke; = 4 mu? = 4m(v::v;) = {x32(6.21~2.203).[621 - 21200) = *3.2 ((6.2)2 + (2-2)2) = 4*

Add a comment
Know the answer?
Add Answer to:
A stone with a mass of 3.20 kg is moving with velocity (6.20 - 2.209) m/s....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A rock with a mass of 3.80 kg is moving with velocity (6.609 - 1.409) m/s....

    A rock with a mass of 3.80 kg is moving with velocity (6.609 - 1.409) m/s. (HINT: v2 = v.v.) (a) What is the rock's kinetic energy (in )) at this velocity? 86.48 (b) Find the net work (in )) on the rock if its velocity changes to (8.00î + 4.00)) m/s. 25.41 x Find the square of the velocity using the hint given, and then use the definition of kinetic energy to calculate the new kinetic energy. The change...

  • A 2.80-kg object has a velocity (6.20 î - 2.40 ĵ) m/s. (Note: From the definition...

    A 2.80-kg object has a velocity (6.20 î - 2.40 ĵ) m/s. (Note: From the definition of the dot product, v2 = v with arrow · v with arrow.) (a) What is its kinetic energy at this moment? (b) Find the net work done on the object if its velocity changes to (8.00 î+ 4.00 ĵ) m/s. J

  • 3 A block of mass 15 kg is initially moving with velocity 20 m/s. If a...

    3 A block of mass 15 kg is initially moving with velocity 20 m/s. If a net 800 J of work is done by the force, calculate the final velocity attained by the block. [Work- Energy theorem)

  • 1. A 30.00 kg mass moving with the velocity of 10 m/s. The momentum of the...

    1. A 30.00 kg mass moving with the velocity of 10 m/s. The momentum of the body will be A. 144.2 kg m/s. B. 187.8 kg m/s. C. 320.0 kg m/s. D. 442.4 kg m/s. E. None of the above 2. Out of the following which one is not a vector quantity? A. Force B. Impulse C. Mass D. velocity 3. Impulse is the product of which two quantities? A. Mass and Time B. Mass and Momentum C. Force and...

  • A stone with mass m = 0.700 kg is thrown vertically upward into the air with...

    A stone with mass m = 0.700 kg is thrown vertically upward into the air with an initial kinetic energy of 610 J. The drag force acting on the stone throughout its flight is constant, independent of the velocity of the stone, and has a magnitude of 0.600 N. What is the maximum height reached by the stone? What is the speed of the stone upon impact with the ground?

  • A large cruise ship of mass 6.20 ✕ 107 kg has a speed of 11.4 m/s...

    A large cruise ship of mass 6.20 ✕ 107 kg has a speed of 11.4 m/s at some instant. (a) What is the ship's kinetic energy at this time? J (b) How much work is required to stop it? (Give the work done on the ship. Include the sign of the value in your answer.) J (c) What is the magnitude of the constant force required to stop it as it undergoes a displacement of 2.70 km? N

  • And the following problem: A mass m 12 kg, has an initial velocity (a) Calculate the...

    And the following problem: A mass m 12 kg, has an initial velocity (a) Calculate the initial kinetic energy of this mass. (b) Due to a nonzero net force on the mass, the velocity of the mass changes in time. Here's the FINAL velocity: v,) (44i -(2.8)j mn Calculate the NET work done from the initial to final point.

  • A bead of mass m = 6.20 kg is released from point A and slides on...

    A bead of mass m = 6.20 kg is released from point A and slides on the frictionless track as shown in the figure below. The height of A is ha = 6.30 m. (a) Determine the bead's speed at points B and C. point B m/s point C m/s (b) Determine the net work done by the force of gravity in moving the bead from A to C. J

  • A cart of mass 0.20 kg starts moving at velocity 3.0 m/s collides inelastically with an...

    A cart of mass 0.20 kg starts moving at velocity 3.0 m/s collides inelastically with an initially stationary cart of mass 0.40 kg. (A) If the carts stick together, what is their combined velocity immediately after the collision? (B) How much kinetic energy is lost in the collision?

  • Sphere A, of mass 0.600 kg, is initially moving to the right at 4.00 m/s. Sphere B, of mass 1.80 kg, is initially to the...

    Sphere A, of mass 0.600 kg, is initially moving to the right at 4.00 m/s. Sphere B, of mass 1.80 kg, is initially to the right of sphere A and moving to the right at 2.00 m/s. After the two spheres collide, sphere B is moving at 3.00 m/s in the same direction as before. (a) What is the velocity (magnitude and direction) of sphere A after this collision? (b) Is this collision elastic or inelastic? (c) Sphere B then...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT