If 0.360 moles of a monoprotic weak acid (Ka = 8.6 × 10-5) is titrated with...
If 0.360 moles of a monoprotic weak acid (Ka = 8.6 × 10-5) is titrated with NaOH, what is the pH of the solution at the half-equivalence point?
Homework Answers
at half equivalence point 50% acid becomes salt
so at half equivalence point [salt] = [acid]
for acidic buffer
pH = pKa + log [salt] / [acid]
pKa = - log Ka = - log [8.6 x 10-5]
pKa = 4.06
as [salt] = [acid]
log [salt] /[acid] = 0
pH = pKa
pH = 4.06
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