If I is the current in the external resistor R and r is the internal resistance of the cell, the equation for the whole circuit is:
E = I(R + r) …….(i)
For the same current in the external resistor R, the terminal voltage is given by:
V = IR …….(ii)
Use equations (i) and (ii) to solve for r by eliminating I and write this equation the form:
y = mx + b
Identify the independent variable and the dependent variable.
Draw an appropriate graph and measure its slope.
Use the slope of the graph to obtain a value of the internal resistance r of the cell.
i need helpppppppppppppp how the graph looks like ????
r = PD/(V/R) PD =[ E -- V]
r = 2.22/(4,43/1)
r =2.22/4,43
r= 1,5 ohms approx
V is the terminal voltage of supply due to current flow through
external resistance
therefore the potential difference of EMF and voltage is due to
current flow through
the internal resistance (r)
If I is the current in the external resistor R and r is the internal resistance...
If I is the current in the external resistor R and r is the internal resistance of the cell, the equation for the whole circuit is: E = I(R + r) …….(i) For the same current in the external resistor R, the terminal voltage is given by: V = IR …….(ii) Use equations (i) and (ii) to solve for r by eliminating I and write this equation the form: y = mx + b Identify...
If I is the current in the external resistor R and r is the internal resistance of the cell, the equation for the whole circuit is: E = I(R + r) …….(i) For the same current in the external resistor R, the terminal voltage is given by: V = IR …….(ii) Use equations (i) and (ii) to solve for r by eliminating I and write this equation the form: y = mx + b...
1. Measure ands record the e.m.f E of the given cell. emf=5.65V 2. Connect an external resistance R = 1 W and measure the terminal voltage V across the resistor. 1 ohm V=4.45V 3. Repeat step 2 using six different values of R each time measuring V. Tabulate the values of V and R. 1 ohm 4.45 V 2 ohm 4.64 3 ohm 4.77 V 4 ohm 4.88V 5 ohm 4.96V 10 ohm 5.16V 20 ohm 5.32 V...
I'm having trouble with numbers 5 to 7. I need help working out the equation in question 5 so I can graph it for number 6 and using the slope from the graph to solve number 7. 1. 2 points Measure ands record the em.f E of the given cell. E = 5.65 v 2. Connect an external resistance R=12 and measure the terminal voltage V across the resistor. 2 points 1 ohm = 4.42 3. 1 Repeat step 2...
I'm having trouble with numbers 5 to 7. I need help working out the equation in question 5 so I can graph it for number 6 and using the slope from the graph to solve number 7. 1. 2 points Measure ands record the em.f E of the given cell. E = 5.65 v 2. Connect an external resistance R=12 and measure the terminal voltage V across the resistor. 2 points 1 ohm = 4.42 3. 1 Repeat step 2...
E = I(R + r) .... (i) V = IR ...(ii) Use equations (i) and (ii) to solve for r by eliminating I and write this equation the form: y = mx + b Identify the independent variable and the dependent variable
Supposed we use an ideal resistor of resistance R and vary the voltage applied as the independent variable and measure the current as the dependent variable. Voltage is graphed as the abscissa and current as the ordinate. What is the expected slope? Expected y-intercept?
E = I(R + r) .... (i) V = IR ...(ii) Eliminate R from equations (i) and (ii) in 4 above and obtain an equation connecting E, V, I and r. Identify the independent and dependent variable in this equation and write it in the y = mx + b form.
A battery has an emf of 12.0 V and an internal resistance of 0.210 Q. Its terminals are connected to a load resistance of 3.00 . Circuit diagram of a source of emf (in this case, a battery), of internal resistance r, connected to an external resistor of resistance R. for ning R (a) Find the current in the circuit and the terminal voltage of the battery. SOLUTION Conceptualize Study the figure, which shows a circuit consistent with the problem...
(ii) Eliminate R from equations (i) and (ii) in 4 above and obtain an equation connecting E, V, I and r. Identify the independent and dependent variable in this equation and write it in the y = mx + b form. eq 1E=I(R+r) eq 2 V=IR