Question

At what distance is the first image from the first lens? Answer in units of m. What is the magnification of the first image? At what distance is the second image from the second lens? Answer in units of m. What is the magnification of the final image, when compared to the initial object?

Answer 1

part 1)

1/v = 1/f - 1/u

1/v = 1/5.9 - 1/10

v = 14.39 m

part b )

m = -v/u = -1.439

part c )

u' = 14.39 - 9.46 = 4.93 m

1/v' = 1/f' - 1/u'

1/v =(1/-2.4) - (1/4.93)

v = -1.614 m

m' = v'/u' = 0.327

M = m*m' = -0.4712