Question

A catapult launches a rock at a 50° angle with respect to the horizontal. Find the maximum height attained if the speed of the rock at its highest point is 25 m/s.

Answer 1

here,
V = 25 m/s
Theta = A = 50 degree

Let h be tha maximu height attained by rock, in projectile motion we have,

H = Vo^2 * sin^2A /2g
Where,
Vo = Velocity
g = acceleration due to gravity

So,

Hmax = 25^2 * sin^2(50) / 2*9.8

Hmax = 14.83 m

The maximum Height attained by rock will be 14.83 m